Adaptive Regularized Submodular Maximization
This addresses an incremental improvement in adaptive submodular maximization by incorporating cost functions, relevant for optimization in sequential decision-making under uncertainty.
The paper tackles the problem of maximizing the difference between an adaptive submodular revenue function and a modular cost function under a cardinality constraint, developing policies with performance guarantees such as (1-1/e-ε) approximation for monotone cases and 1/e approximation for general cases.
In this paper, we study the problem of maximizing the difference between an adaptive submodular (revenue) function and an non-negative modular (cost) function under the adaptive setting. The input of our problem is a set of $n$ items, where each item has a particular state drawn from some known prior distribution $p$. The revenue function $g$ is defined over items and states, and the cost function $c$ is defined over items, i.e., each item has a fixed cost. The state of each item is unknown initially, one must select an item in order to observe its realized state. A policy $π$ specifies which item to pick next based on the observations made so far. Denote by $g_{avg}(π)$ the expected revenue of $π$ and let $c_{avg}(π)$ denote the expected cost of $π$. Our objective is to identify the best policy $π^o\in \arg\max_πg_{avg}(π)-c_{avg}(π)$ under a $k$-cardinality constraint. Since our objective function can take on both negative and positive values, the existing results of submodular maximization may not be applicable. To overcome this challenge, we develop a series of effective solutions with performance grantees. Let $π^o$ denote the optimal policy. For the case when $g$ is adaptive monotone and adaptive submodular, we develop an effective policy $π^l$ such that $g_{avg}(π^l) - c_{avg}(π^l) \geq (1-\frac{1}{e}-ε)g_{avg}(π^o) - c_{avg}(π^o)$, using only $O(nε^{-2}\log ε^{-1})$ value oracle queries. For the case when $g$ is adaptive submodular, we present a randomized policy $π^r$ such that $g_{avg}(π^r) - c_{avg}(π^r) \geq \frac{1}{e}g_{avg}(π^o) - c_{avg}(π^o)$.